A. ProblemThe purpose of this lab is to observe how enzymes act on substances to produce product. We will observe how enzyme activity is altered when the enzyme environment's pH is changed.
B. HypothesisIf I make the pH of the lactase reaction more acidic, I believe that the products formed will be more than what is normally produced because the acid will have a positive charge bringing protons that ill attract with the electrons causing a reaction.
If I make the pH of the lactase reaction more basic, I believe that the products formed will be less than what is normally produced because the base will bring in a negative charge and it will repel with the other electrons. |
C. materials
D. Procedure
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E. ResultsI observed that in the table the most amount of product was formed with the pH seven. I also observed that the amount of product formed for four grams and eight grams of lactose was the same. I observed that the most amount of product formed was with the four and eight grams of lactose. The least amount of product was formed when the least amount of substrate was added. The least amount of product made was 19,000,000 with the .5 grams of lactose. the most amount of product formed was 350,000,000 when four and eight grams of lactose where added.
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Number of Molecules Formed Per Minute in Varying Levels of pH |
F. Conclusion
Virtual Lab> Journal Questions
1) It has a positive slope so it will increase because the more substrate added the more product should be formed. It does not increase because there may not be enough enzymes.
2) The maximum amount is at trial four and five given four grams and eight grams.
3) Because there is less substrate to bind with the enzymes.
4) Lactose likes a neutral pH like in pH seven where it produces the most amount of product.
5) The reactions also react based on the temperature. If the temperature is to hot then the enzymes may not react.
6) At about pH seven.
The purpose for this experiment is to see how enzymes react in substances to produce product. My hypothesis was that if more acid was added there would be more product formed. My hypothesis was disproven because the most amount of product was formed when the enzyme was neutral. I think I was disproven because the substrate and the enzyme could bond without anything messing up the enzyme's active site. I learned that if it is not neutral it can mess up the enzyme's active site which will then not allow the enzyme and the substrate to bond. As evidenced by the data earned from the graph and the table. The pH that is optimal for the enzyme is pH seven according to my data and graph. The enzyme likes the pH seven as evidenced by the graph and data table which shows that the most amount o product is formed in the pH seven for every trial in the varying amounts of substrate. If the enzyme is not in the optimal pH the active site may be denaturalized which will not allow the maximum amount of enzymes to bond with the maximum amount of substrate. The most product is formed when the pH is at seven and when four and eight grams of lactose are added. There is a positive slope as the pH rises to pH seven but then goes down when the pH is higher than seven. Even if you add a large quantity of lactose it may not change as evidenced by the graph and data table. As it shows four grams and eight grams of lactose give the same amount of product which could be because there is not enough enzymes to bond with the substrate. If I could change this lab I would heat up the enzyme before adding the substrate to see if that messes up the active site of the enzyme. The things that may go wrong during this lab may be getting the exact measurements, another thing that may go wrong can be the temperature that may affect the active site of the enzyme.
1) It has a positive slope so it will increase because the more substrate added the more product should be formed. It does not increase because there may not be enough enzymes.
2) The maximum amount is at trial four and five given four grams and eight grams.
3) Because there is less substrate to bind with the enzymes.
4) Lactose likes a neutral pH like in pH seven where it produces the most amount of product.
5) The reactions also react based on the temperature. If the temperature is to hot then the enzymes may not react.
6) At about pH seven.
The purpose for this experiment is to see how enzymes react in substances to produce product. My hypothesis was that if more acid was added there would be more product formed. My hypothesis was disproven because the most amount of product was formed when the enzyme was neutral. I think I was disproven because the substrate and the enzyme could bond without anything messing up the enzyme's active site. I learned that if it is not neutral it can mess up the enzyme's active site which will then not allow the enzyme and the substrate to bond. As evidenced by the data earned from the graph and the table. The pH that is optimal for the enzyme is pH seven according to my data and graph. The enzyme likes the pH seven as evidenced by the graph and data table which shows that the most amount o product is formed in the pH seven for every trial in the varying amounts of substrate. If the enzyme is not in the optimal pH the active site may be denaturalized which will not allow the maximum amount of enzymes to bond with the maximum amount of substrate. The most product is formed when the pH is at seven and when four and eight grams of lactose are added. There is a positive slope as the pH rises to pH seven but then goes down when the pH is higher than seven. Even if you add a large quantity of lactose it may not change as evidenced by the graph and data table. As it shows four grams and eight grams of lactose give the same amount of product which could be because there is not enough enzymes to bond with the substrate. If I could change this lab I would heat up the enzyme before adding the substrate to see if that messes up the active site of the enzyme. The things that may go wrong during this lab may be getting the exact measurements, another thing that may go wrong can be the temperature that may affect the active site of the enzyme.